![]() ![]() Plot the original data, determine if they are related and, if so, the time delay between them. They are believed to be involved in the same function but separated by one or more neuronal junctions that impart a delay to the signal. is 1/10 s and the phase in deg is the ratio of the time delay to the period, times 360.]please solve with MATLABįile neural_data.mat contains two waveforms, x and y, that were recorded from two different neurons in the brain with a sampling interval of 0.2 ms. Plot the cross-correlation function and find the lag at which the maximum (or minimum) correlation occurs. 2.28 Use MATLAB and cross-correlation to find the phase shift between 10-Hz sinusoids found as variables x and y in file sines1.mat. print ac v(1,2) v(2,3) v(3,4) v(4,0) * Voltage across pairs of similar components. ac lin 1 60 60 * Voltage across each component. Netlist (make a text file containing the following text, verbatim): These two resistors are entirely unnecessary in the real circuit. This is a “fix” for one of SPICE’s quirks, to avoid it from seeing the capacitors as open circuits in its analysis. The two large-value resistors R bogus1 and R bogus1 are connected across the capacitors to provide a DC path to ground in order that SPICE will work. The polar magnitudes of the results should closely agree with your voltmeter readings. Given that the power supply frequency is 60 Hz (household power frequency in the United States), calculate impedances for all components and determine all voltage drops using Ohm’s Law (E=IZ I=E/Z Z=E/I). Likewise, this tells you that both the capacitors’ voltage drop waveforms are in-phase with each other. This voltage drop, like the drop measured across the two resistors, will equal the sum of the voltage drops measured across each capacitor separately. Measure voltage dropped across both capacitors at once. This tells you that both the resistors’ voltage drop waveforms are in-phase with each other since they add simply and directly. This voltage drop will equal the sum of the voltage drops measured across each resistor separately. Try measuring voltage dropped across both resistors at once. Therefore the period of this function is equal to 2 /6 or /3. To find amplitude, look at the coefficient in front of the sine function. Taking phase angle into consideration, they do add up to equal the total, but a voltmeter doesn’t provide phase angle measurements, only amplitude. Next, apply the above numbers to find amplitude, period, phase shift, and vertical shift. This is due to phase shifts in the circuit: voltage dropped across the capacitors is out-of-phase with voltage dropped across the resistors, and thus the voltage drop figures do not add up as one might expect. You will discover that the voltage drops do not add up to equal the total voltage. Measure total (supply) voltage with the same voltmeter. How out-of-phase AC voltages do not add algebraically, but according to vector (phasor) arithmeticīuild the circuit and measure voltage drops across each component with an AC voltmeter.Lessons In Electric Circuits, Volume 2, chapter 4: “ Reactance and Impedance-Capacitive” Lessons In Electric Circuits, Volume 2, chapter 1: “ Basic AC Theory” ![]() ![]() Avoid capacitors with any kind of polarity marking, as these will be destroyed when powered by AC! I recommend ceramic disk capacitors because they are insensitive to polarity (non-polarized), inexpensive, and durable. Two capacitors, 0.1 ♟ each, non-polarized (Radio Shack catalog # 272-135). ![]()
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