![]() which represent root and current directory, respectively. Finding Files via Last Time Access with Output. Then the -printf action outputs the last time access ( a) of files or directories and the filenames ( p ), each on a new line ( ), as shown below. This is the starting point to search files. In the output above bash: is the command for which you want to get information, /bin/bash is the path to the binary file, /etc/bash.bashrc is the source file, and /usr/share/man/man1/bash.1. The command line below lets you find files accessed within the past day ( -atime 0 ). Where, /path is the path where file is expected to be found. Syntax: find / -name apk ls Output How to List only Directories If you want to search only the directories and skip the file names use the -type d. SOLVED: After the discussion below, I put this in my. Below is the basic syntax of the find command: find /path/ -type f -name file-to-search. Ideally, I'd like to lose the quotation marks too, but I'm guessing that might not be possible because the shell will expand them before calling "fn".Īny advice would be greatly appreciated and will postpone carpal tunnel syndrome. But find is a super duper mega power user tool that you can very easily hurt yourself with Example: when you do the command. This is unusual - most commands are NOT capable of globbing and rely entirely on the shell to expand globs. ![]() ![]() (I used to be able to do this in csh, but now I'm using bash.) If an alias or function named "fn" were set properly, I could save some time by just typing: fn "*.txt" Both the find command and the shell are capable of file globbing. name "*.txt" -printīut what I'd really like is an alias or function that will properly pass the wildcard. I've long used the find command for finding files and directories in the current directory and all subdirectories that match a pattern: find. ![]()
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